2.9 Chemical equilibria
Posted by: intechemistry on: September 23, 2010
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7 Responses to "2.9 Chemical equilibria"
May 11, 2011 at 6:09 pm
Because in answer C, the vertical line representing t(eqm) has the concentration of A and Y changing after that time. It therefore doesn’t correspond to the the definition of eqm.
In answer B, at t(eqm) onwards, the concentrations of X and Y are const.
As far as I can tell, there isn’t anything wrong with the graph other than that.
May 19, 2012 at 5:14 pm
sir. is the graph for dynamic equilibrium in facer pg 250 correct? it contradicts with the answer for q8, section A, june 2010 unit 2 paper.
May 19, 2012 at 5:52 pm
My AS level Facer is in my office. Please tell me how you think it contradicts?
May 20, 2012 at 6:49 am
The graph given in Facer is similar to the one in quest 8 june 2010 option C. the difference is that the line after the t eqm is a single straight line. But the answer for the question is B. which graph is accepted?
May 20, 2012 at 11:45 am
5, Kosher, May 20, 2012 at 6:49 am
Graphs B and C could happen in terms of concentration values during a chemical reaction. However graph C is wrong ONLY because the horizontal line supposedly showing the time at which equilibrium is reached is wrong because after that point, the concentrations of X and Y still change. So Facer could have either graph. It’s not statistically likely that by random chance initial concentrations of X and Y are chosen which results in them having equal concentration at the end of the reaction, hence graphs of type B are usually chosen to describe a system.
May 23, 2012 at 5:03 pm
sir i think the graph on page 250 is correct. I read the the other source- notes it says the same. and ask to take extra caution on the y-axis (whether its r.o.r or con) ……btw for endothermic reaction the reactants are thermodynamically stable to products whilst the reverse is true for exothermic reaction ryte?
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May 11, 2011 at 5:46 pm
hi sir,
[Chemistry Unit 2 June 2010, Section A, Q8]
Why is the answer B, and not C?